derivative of-sin(2x2+cos(2x)2)

解答

\frac{d}{d x} (- sin (2 x) \cdot 2 + cos (2 x) \cdot 2)

- 4 cos (2 x) - 4 sin (2 x)

求解步骤

\frac{d}{d x} (- sin (2 x) \cdot 2 + cos (2 x) \cdot 2)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (sin (2 x) \cdot 2) + \frac{d}{d x} (cos (2 x) \cdot 2)

\frac{d}{d x} (sin (2 x) \cdot 2) = 4 cos (2 x)

\frac{d}{d x} (cos (2 x) \cdot 2) = - 4 sin (2 x)

= - 4 cos (2 x) - 4 sin (2 x)

t an g e n t - 3 x^{2} + 6 x + 4

d er i v a t i v e f (x) = 2 e^{x} + \frac{2}{3 x}

n = 1 \sum \infty n^{5} (1 + n^{6})^{1}

\int \frac{z ^{3}}{3 5 + z ^{4}} d z

\frac{d y}{d x} = 5 - y