integral from 1 to 4 of (4x^2-2x)

Lösung

\int_{1}^{4} (4 x^{2} - 2 x) d x

69

Schritte zur Lösung

\int_{1}^{4} 4 x^{2} - 2 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 4 x^{2} d x - \int_{1}^{4} 2 x d x

\int_{1}^{4} 4 x^{2} d x = 84

\int_{1}^{4} 2 x d x = 15

= 84 - 15

Vereinfache

= 69

(\frac{3 y ^{2} - x ^{2}}{y ^{5}}) \frac{d y}{d x} + \frac{x}{2 y ^{4}} = 0

\frac{\partial}{\partial x} (x (x^{2} + 1))

in v erse l a pl a ce \frac{3}{s - 5} - \frac{2}{s + 7}

\int b^{x} d x

\frac{d y}{d x} = \frac{( x ^{2} + 1 )}{e ^{y}}