What is the tangent of y=(14)/(1+e^{-x)},(0,7) ?

The tangent of y=(14)/(1+e^{-x)},(0,7) is y= 7/2 x+7

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tangent of y=(14)/(1+e^{-x)},(0,7)

tangent of

y = \frac{14}{1 + e ^{- x}}, (0, 7)

y = \frac{7}{2} x + 7

Solution steps

Find the slope of

y = \frac{14}{1 + e ^{- x}} : \frac{d y}{d x} = \frac{14 e ^{- x}}{( 1 + e ^{- x} ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{2}

Find the line with slope m=

\frac{7}{2}

and passing through

(0, 7) : y = \frac{7}{2} x + 7

y = \frac{7}{2} x + 7

What is the tangent of y=(14)/(1+e^{-x)},(0,7) ?
The tangent of y=(14)/(1+e^{-x)},(0,7) is y= 7/2 x+7