y^{''}+4y=e-t

Lösung

y^{^{''}} + 4 y = e - t

y = c_{1} cos (2 t) + c_{2} sin (2 t) - \frac{t}{4} + \frac{e}{4}

Schritte zur Lösung

y^{''} (t) + 4 y = e - t

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t) - \frac{t}{4} + \frac{e}{4}

y = c_{1} cos (2 t) + c_{2} sin (2 t) - \frac{t}{4} + \frac{e}{4}

\int \frac{8}{3 x ^{2}} d x

y^{^{''}} - 2 y^{^{'}} = 6 e^{2 x}

\int \frac{9 x ^{2} + 6 x + 9}{x ^{3} - 1} d x

l a pl a ce t r an s f or m e^{2 t} sin (2 t j)

d er i v a t i v e y = c cos (t) + t^{2} sin (t)