What is (\partial)/(\partial y)(x+ycos(x)) ?

The answer to (\partial)/(\partial y)(x+ycos(x)) is cos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial y)(x+ycos(x))

\frac{\partial}{\partial y} (x + y cos (x))

cos (x)

Solution steps

\frac{\partial}{\partial y} (x + y cos (x))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (y cos (x))

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y cos (x)) = cos (x)

= 0 + cos (x)

Simplify

= cos (x)

What is (\partial)/(\partial y)(x+ycos(x)) ?
The answer to (\partial)/(\partial y)(x+ycos(x)) is cos(x)