What is the derivative of (45-0.12xx) ?

The derivative of (45-0.12xx) is -0.24x+45

What is the first derivative of (45-0.12xx) ?

The first derivative of (45-0.12xx) is -0.24x+45

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\frac{d}{d x} ((45 - 0.12 x) x)

- 0.24 x + 45

Solution steps

\frac{d}{d x} ((45 - 0.12 x) x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 45 - 0.12 x, g = x

= \frac{d}{d x} (45 - 0.12 x) x + \frac{d x}{d x} (45 - 0.12 x)

\frac{d}{d x} (45 - 0.12 x) = - 0.12

\frac{d x}{d x} = 1

= (- 0.12) x + 1 \cdot (45 - 0.12 x)

Simplify

(- 0.12) x + 1 \cdot (45 - 0.12 x) : - 0.24 x + 45

= - 0.24 x + 45

What is the derivative of (45-0.12xx) ?
The derivative of (45-0.12xx) is -0.24x+45
What is the first derivative of (45-0.12xx) ?
The first derivative of (45-0.12xx) is -0.24x+45