What is the solution for (dy)/(dx)=e^{x+2y} ?

The solution for (dy)/(dx)=e^{x+2y} is y=-(ln(-2e^x-c_{1}))/2

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(dy)/(dx)=e^{x+2y}

\frac{d y}{d x} = e^{x + 2 y}

y = - \frac{ln ( - 2 e ^{x} - c _{1} )}{2}

Solution steps

\frac{d y}{d x} = e^{x + 2 y}

Solve separable ODE:

y = - \frac{ln ( - 2 e ^{x} - c _{1} )}{2}

y = - \frac{ln ( - 2 e ^{x} - c _{1} )}{2}

\frac{d y}{d x} = y (y + 2)

f (x) = 2 \cdot x

n = 1 \sum \infty \frac{2}{n ^{2} + 6 n + 8}

\frac{d}{d x} (\frac{x - 2}{x ^{2} - 4})

t an g e n t y = x^{2} + x + 9, at x = 2

What is the solution for (dy)/(dx)=e^{x+2y} ?
The solution for (dy)/(dx)=e^{x+2y} is y=-(ln(-2e^x-c_{1}))/2