What is the solution for y^{''}+2y=-12x ?

The solution for y^{''}+2y=-12x is y=c_{1}cos(sqrt(2)x)+c_{2}sin(sqrt(2)x)-6x

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y^{''}+2y=-12x

y^{^{''}} + 2 y = - 12 x

y = c_{1} cos (2 x) + c_{2} sin (2 x) - 6 x

Solution steps

y^{''} (x) + 2 y = - 12 x

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) - 6 x

y = c_{1} cos (2 x) + c_{2} sin (2 x) - 6 x

x \to \infty lim (x)

\int \frac{2 x}{3 6 - 5 x ^{2}} d x

l c m f (x) =, 4 x^{3} + 2 t + 9

f (x) = (2 x + 3)^{1.4}

\int \frac{( x ^{2} + 1 ) ( x ^{2} - 2 )}{x ^{\frac{2}{3}}} d x

What is the solution for y^{''}+2y=-12x ?
The solution for y^{''}+2y=-12x is y=c_{1}cos(sqrt(2)x)+c_{2}sin(sqrt(2)x)-6x