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人気のある微分積分 >

2y^'+4y=-8y^3

解

2 y^{^{'}} + 4 y = - 8 y^{3}

解

y = \frac{1}{e ^{4 t - c_{1}} - 2}, y = - \frac{1}{e ^{4 t - c_{1}} - 2}

解答ステップ

2 y^{'} (t) + 4 y = - 8 y^{3}

ベルヌーイ ODE を解く:

y = \frac{1}{e ^{4 t - c_{1}} - 2}, y = - \frac{1}{e ^{4 t - c_{1}} - 2}

y = \frac{1}{e ^{4 t - c_{1}} - 2}, y = - \frac{1}{e ^{4 t - c_{1}} - 2}

グラフ

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