What is the derivative of 8\sqrt[4]{x} ?

The derivative of 8\sqrt[4]{x} is 2/(x^{3/4)}

What is the first derivative of 8\sqrt[4]{x} ?

The first derivative of 8\sqrt[4]{x} is 2/(x^{3/4)}

\frac{d}{d x} (8 4 x)

\frac{2}{x ^{\frac{3}{4}}}

Solution steps

\frac{d}{d x} (8 4 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (4 x)

Apply radical rule:

n a = a^{\frac{1}{n}}

= 8 \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 \cdot \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

8 \cdot \frac{1}{4} x^{\frac{1}{4} - 1} : \frac{2}{x ^{\frac{3}{4}}}

= \frac{2}{x ^{\frac{3}{4}}}

y^{^{''}} + 4 y = 3 sin (2 x)

d er i v a t i v e \frac{9}{x + 2}

\frac{\partial}{\partial x} (x y e^{z} + x - z^{2} - 3)

\int sin^{3} (10 x) d x

t an g e n t y = x^{2} - x + 4, at x = 4

What is the derivative of 8\sqrt[4]{x} ?
The derivative of 8\sqrt[4]{x} is 2/(x^{3/4)}
What is the first derivative of 8\sqrt[4]{x} ?
The first derivative of 8\sqrt[4]{x} is 2/(x^{3/4)}