What is the integral of sin(pi/2 x) ?

The integral of sin(pi/2 x) is -2/pi cos(pi/2 x)+C

integral of sin(pi/2 x)

\int sin (\frac{π}{2} x) d x

- \frac{2}{π} cos (\frac{π}{2} x) + C

Solution steps

\int sin (\frac{π}{2} x) d x

Apply u-substitution

= \int sin (u) \frac{2}{π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{π} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{2}{π} (- cos (u))

Substitute back

u = \frac{π}{2} x

= \frac{2}{π} (- cos (\frac{π}{2} x))

Simplify

= - \frac{2}{π} cos (\frac{π}{2} x)

Add a constant to the solution

= - \frac{2}{π} cos (\frac{π}{2} x) + C

x \to - 1 lim (- f (x))

\int_{l n (\frac{5}{6})}^{\infty} \frac{e ^{x}}{36 e ^{2 x} + 25} d x

\frac{d y}{d x} + \frac{3}{x} y = \frac{ln ( x )}{x ^{2}}

\int - \frac{1}{x ^{2} - 1} d x

y^{^{'}} = sec^{2} (x) (2 + y)^{2}, y (π) = - 5

What is the integral of sin(pi/2 x) ?
The integral of sin(pi/2 x) is -2/pi cos(pi/2 x)+C