y^{''}-9y^'+20y=0

Lösung

y^{^{''}} - 9 y^{^{'}} + 20 y = 0

y = c_{1} e^{5 t} + c_{2} e^{4 t}

Schritte zur Lösung

y^{''} (t) - 9 y^{'} (t) + 20 y = 0

Solve linear ODE:

y = c_{1} e^{5 t} + c_{2} e^{4 t}

y = c_{1} e^{5 t} + c_{2} e^{4 t}

x \to 4 lim (\frac{x - 5}{x - 4})

\frac{\partial}{\partial y} (\frac{y ^{2}}{x})

\frac{d}{d x} (\frac{x ^{4}}{4} - \frac{9}{2} x^{2} + 1)

\int (x + y)^{2} d x

x \to 0 lim (\frac{sin ( 4 x )}{tan ( 3 x )})