y^'=(2xy^3)/(1-x^2y^2)

解答

y^{^{'}} = \frac{2 x y ^{3}}{1 - x ^{2} y ^{2}}

y = - \frac{c _{1} + c _{1}^{2} - 4 x ^{2}}{2 x ^{2}}, y = - \frac{c _{1} - c _{1}^{2} - 4 x ^{2}}{2 x ^{2}}

求解步骤

y^{'} (x) = \frac{2 x y ^{3}}{1 - x ^{2} y ^{2}}

求解恰当方程:

y = - \frac{c _{1} + c _{1}^{2} - 4 x ^{2}}{2 x ^{2}}, y = - \frac{c _{1} - c _{1}^{2} - 4 x ^{2}}{2 x ^{2}}

y = - \frac{c _{1} + c _{1}^{2} - 4 x ^{2}}{2 x ^{2}}, y = - \frac{c _{1} - c _{1}^{2} - 4 x ^{2}}{2 x ^{2}}

f^{^{'}} (x) = - 3

x \to 0 lim (7 - x^{2})

x \to \infty lim (- x^{3})

\int_{1}^{4} x^{2} d x

x \to 1 + lim (x^{2} + 3)