derivative of sqrt(16x^2+9)

Lösung

\frac{d}{d x} (16 x^{2} + 9)

\frac{16 x}{16 x ^{2} + 9}

Schritte zur Lösung

\frac{d}{d x} (16 x^{2} + 9)

Wende die Kettenregel an:

\frac{1}{2 16 x ^{2} + 9} \frac{d}{d x} (16 x^{2} + 9)

= \frac{1}{2 16 x ^{2} + 9} \frac{d}{d x} (16 x^{2} + 9)

\frac{d}{d x} (16 x^{2} + 9) = 32 x

= \frac{1}{2 16 x ^{2} + 9} \cdot 32 x

Vereinfache

\frac{1}{2 16 x ^{2} + 9} \cdot 32 x : \frac{16 x}{16 x ^{2} + 9}

= \frac{16 x}{16 x ^{2} + 9}

\int_{- 1}^{1} 1.5 x^{3} d x

d er i v a t i v e f (x) = (x^{2} - 5 x + 2) (x - \frac{2}{x})

\int_{0}^{0.6} 3000 x d x

\int \frac{1}{( x + 2 ) ^{2}} d x

\int \frac{1}{( x + 1 ) ( x + 2 ) ^{2}} d x