What is (\partial)/(\partial x)((x-y)/(30-y)) ?

The answer to (\partial)/(\partial x)((x-y)/(30-y)) is 1/(30-y)

(\partial)/(\partial x)((x-y)/(30-y))

\frac{\partial}{\partial x} (\frac{x - y}{30 - y})

\frac{1}{30 - y}

Solution steps

\frac{\partial}{\partial x} (\frac{x - y}{30 - y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{30 - y} \frac{\partial}{\partial x} (x - y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{30 - y} (\frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{30 - y} (1 - 0)

Simplify

= \frac{1}{30 - y}

\frac{d}{d x} (ln (3^{x} sec^{3} (4 x)))

\int_{- 2}^{5} 2 e^{x} (5 x^{2} + 3) d x

\int x 4 + x d x

n or ma l f (x) = x^{3} - 3 x^{2} + 5, at x = - 1

\int_{0}^{6} 2

What is (\partial)/(\partial x)((x-y)/(30-y)) ?
The answer to (\partial)/(\partial x)((x-y)/(30-y)) is 1/(30-y)