laplacetransform [\delta(t+1)]

Lösung

laplace transformation

[δ (t + 1)]

1

Schritte zur Lösung

L {δ (t + 1)}

Vereinfache

= L {δ (t - (- 1))}

Wende Laplace-Transformationstabelle an:

L {δ (t - c)} = 1, c \leq 0

L {δ (t + 1)} = 1

= 1

\int \frac{- x + 2}{x ^{2} - x + 1} d x

\int sech (\frac{1}{4}) x tanh (\frac{1}{4}) x d x

in v erse l a pl a ce \frac{3 s ^{2}}{( s ^{2} + 4 ) ^{2}}

\int \frac{1}{- x ^{2} + 4 x + 5} d x

\frac{\partial}{\partial x} (r + 2 r^{4} x + 4 x)