What is the derivative of-6sin(x-3x) ?

The derivative of-6sin(x-3x) is -6cos(x)-3

What is the first derivative of-6sin(x-3x) ?

The first derivative of-6sin(x-3x) is -6cos(x)-3

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\frac{d}{d x} (- 6 sin (x) - 3 x)

- 6 cos (x) - 3

Solution steps

\frac{d}{d x} (- 6 sin (x) - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (6 sin (x)) - \frac{d}{d x} (3 x)

\frac{d}{d x} (6 sin (x)) = 6 cos (x)

\frac{d}{d x} (3 x) = 3

= - 6 cos (x) - 3

\int x^{4} (x^{5} - 7)^{6} d x

\frac{8}{s - 3}

\frac{d}{d x} (2 sin (x) + 4 cos (x))

\int 3 t^{5} d t

\frac{d}{d x} (x^{2} cos (π x))

What is the derivative of-6sin(x-3x) ?
The derivative of-6sin(x-3x) is -6cos(x)-3
What is the first derivative of-6sin(x-3x) ?
The first derivative of-6sin(x-3x) is -6cos(x)-3