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Popular Calculus >

integral of (x^3-4x)

Solution

\int (x^{3} - 4 x) d x

Solution

\frac{x ^{4}}{4} - 2 x^{2} + C

Solution steps

\int x^{3} - 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x - \int 4 x d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 4 x d x = 2 x^{2}

= \frac{x ^{4}}{4} - 2 x^{2}

Add a constant to the solution

= \frac{x ^{4}}{4} - 2 x^{2} + C

Graph

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integral of ((x^3))/(sqrt(9-x^2))

\int \frac{( x ^{3} )}{9 - x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral of (x^3-4x) ?
The integral of (x^3-4x) is (x^4)/4-2x^2+C