What is the solution for 4tx(dx)/(dt)=x^2+1 ?

The solution for 4tx(dx)/(dt)=x^2+1 is x=sqrt(c_{1)sqrt(t)-1},x=-sqrt(c_{1)sqrt(t)-1}

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4tx(dx)/(dt)=x^2+1

4 t x \frac{d x}{d t} = x^{2} + 1

x = c_{1} t - 1, x = - c_{1} t - 1

Solution steps

4 t x \frac{d x}{d t} = x^{2} + 1

Solve separable ODE:

x = c_{1} t - 1, x = - c_{1} t - 1

x = c_{1} t - 1, x = - c_{1} t - 1

x \to 1 lim ((3 x - 4)^{2})

d er i v a t i v e f (x) = 5 - x^{2}

\int_{0}^{2} 2 x^{4} e^{- x} d x

a re a y = \frac{1}{14 x ^{2}}, y = x, y = \frac{x}{10}

\frac{d}{d y} (x + y z)

What is the solution for 4tx(dx)/(dt)=x^2+1 ?
The solution for 4tx(dx)/(dt)=x^2+1 is x=sqrt(c_{1)sqrt(t)-1},x=-sqrt(c_{1)sqrt(t)-1}