What is the derivative of x^{4/3}-5 ?

The derivative of x^{4/3}-5 is (4x^{1/3})/3

What is the first derivative of x^{4/3}-5 ?

The first derivative of x^{4/3}-5 is (4x^{1/3})/3

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\frac{d}{d x} (x^{\frac{4}{3}} - 5)

\frac{4 x ^{\frac{1}{3}}}{3}

Solution steps

\frac{d}{d x} (x^{\frac{4}{3}} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{\frac{4}{3}}) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{\frac{4}{3}}) = \frac{4 x ^{\frac{1}{3}}}{3}

\frac{d}{d x} (5) = 0

= \frac{4 x ^{\frac{1}{3}}}{3} - 0

Simplify

= \frac{4 x ^{\frac{1}{3}}}{3}

\int_{- 1}^{3} (1 + 4 x) d x

\frac{d}{d x} (3 x^{3} + 5 x)

\frac{d}{d x} (x (2 - x)^{2})

\frac{\partial}{\partial x} (x e^{- 3 z + 2 y})

d er i v a t i v e arccos (3 x^{2})

What is the derivative of x^{4/3}-5 ?
The derivative of x^{4/3}-5 is (4x^{1/3})/3
What is the first derivative of x^{4/3}-5 ?
The first derivative of x^{4/3}-5 is (4x^{1/3})/3