What is the solution for y^{''}+y=5e^{-8x} ?

The solution for y^{''}+y=5e^{-8x} is y=c_{1}cos(x)+c_{2}sin(x)+1/13 e^{-8x}

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y^{''}+y=5e^{-8x}

y^{^{''}} + y = 5 e^{- 8 x}

y = c_{1} cos (x) + c_{2} sin (x) + \frac{1}{13} e^{- 8 x}

Solution steps

y^{''} (x) + y = 5 e^{- 8 x}

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + \frac{1}{13} e^{- 8 x}

y = c_{1} cos (x) + c_{2} sin (x) + \frac{1}{13} e^{- 8 x}

n = 1 \sum \infty 2 (\frac{2}{3})^{n - 1}

\frac{d}{d x} (cos (x) ln (cos (x)))

\frac{d y}{d t} = 2 y + 2 t^{2} - \frac{10}{3} t

\int 2 z d z

ma c l a u r in x^{5} sin (x)

What is the solution for y^{''}+y=5e^{-8x} ?
The solution for y^{''}+y=5e^{-8x} is y=c_{1}cos(x)+c_{2}sin(x)+1/13 e^{-8x}