What is the d/(dt)(tcos(6t)) ?

The d/(dt)(tcos(6t)) is cos(6t)-6tsin(6t)

What is the first d/(dt)(tcos(6t)) ?

The first d/(dt)(tcos(6t)) is cos(6t)-6tsin(6t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d t} (t cos (6 t))

cos (6 t) - 6 t sin (6 t)

Solution steps

\frac{d}{d t} (t cos (6 t))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = cos (6 t)

= \frac{d t}{d t} cos (6 t) + \frac{d}{d t} (cos (6 t)) t

\frac{d t}{d t} = 1

\frac{d}{d t} (cos (6 t)) = - sin (6 t) \cdot 6

= 1 \cdot cos (6 t) + (- sin (6 t) \cdot 6) t

Simplify

= cos (6 t) - 6 t sin (6 t)

\frac{\partial}{\partial x} (e^{2 x^{3} - 3 y})

\int \frac{x ^{2} - 8 x - 1}{( x - 1 ) ^{2} ( x ^{2} + 1 )} d x

\frac{d}{d x} (2 x + 8)

\frac{d}{d x} ([arctan (3 x)]^{2})

d er i v a t i v e 1680 (2 x + 5)^{4}

What is the d/(dt)(tcos(6t)) ?
The d/(dt)(tcos(6t)) is cos(6t)-6tsin(6t)
What is the first d/(dt)(tcos(6t)) ?
The first d/(dt)(tcos(6t)) is cos(6t)-6tsin(6t)