What is the derivative of ln(2+x^2) ?

The derivative of ln(2+x^2) is (2x)/(2+x^2)

What is the first derivative of ln(2+x^2) ?

The first derivative of ln(2+x^2) is (2x)/(2+x^2)

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\frac{d}{d x} (ln (2 + x^{2}))

\frac{2 x}{2 + x ^{2}}

Solution steps

\frac{d}{d x} (ln (2 + x^{2}))

Apply the chain rule:

\frac{1}{2 + x ^{2}} \frac{d}{d x} (2 + x^{2})

= \frac{1}{2 + x ^{2}} \frac{d}{d x} (2 + x^{2})

\frac{d}{d x} (2 + x^{2}) = 2 x

= \frac{1}{2 + x ^{2}} \cdot 2 x

Simplify

\frac{1}{2 + x ^{2}} \cdot 2 x : \frac{2 x}{2 + x ^{2}}

= \frac{2 x}{2 + x ^{2}}

\int cos (5 x) d x

\int 9 - x^{2} d x

l a pl a ce t r an s f or m g (t) = sin (2 t) sin (t)

\frac{d}{d x} (x^{3} - \frac{1}{x ^{2}})

x \to - \infty lim (x e^{x} - 1)

What is the derivative of ln(2+x^2) ?
The derivative of ln(2+x^2) is (2x)/(2+x^2)
What is the first derivative of ln(2+x^2) ?
The first derivative of ln(2+x^2) is (2x)/(2+x^2)