20y^{''}+11y^'-3y=0

Lösung

20 y^{^{''}} + 11 y^{^{'}} - 3 y = 0

y = c_{1} e^{\frac{t}{5}} + c_{2} e^{- \frac{3 t}{4}}

Schritte zur Lösung

20 y^{''} (t) + 11 y^{'} (t) - 3 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{5}} + c_{2} e^{- \frac{3 t}{4}}

y = c_{1} e^{\frac{t}{5}} + c_{2} e^{- \frac{3 t}{4}}

\frac{d}{d y} (\frac{z}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}})

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