What is the d/(dθ)(sin(θ)+cos(θ)) ?

The d/(dθ)(sin(θ)+cos(θ)) is cos(θ)-sin(θ)

What is the first d/(dθ)(sin(θ)+cos(θ)) ?

The first d/(dθ)(sin(θ)+cos(θ)) is cos(θ)-sin(θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d θ} (sin (θ) + cos (θ))

cos (θ) - sin (θ)

Solution steps

\frac{d}{d θ} (sin (θ) + cos (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (sin (θ)) + \frac{d}{d θ} (cos (θ))

\frac{d}{d θ} (sin (θ)) = cos (θ)

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= cos (θ) - sin (θ)

\int (x + 4) cos (nπ x) d x

\int_{1}^{4} \frac{1}{w ^{2}} d w

\int (x + 2)^{2} (1 - x)^{6} d x

a re a 5 - x^{2}, sin (x), 0, 2

\frac{d ^{4}}{d x ^{4}} (8 e^{- 2 x})

What is the d/(dθ)(sin(θ)+cos(θ)) ?
The d/(dθ)(sin(θ)+cos(θ)) is cos(θ)-sin(θ)
What is the first d/(dθ)(sin(θ)+cos(θ)) ?
The first d/(dθ)(sin(θ)+cos(θ)) is cos(θ)-sin(θ)