What is derivative of f(x)=800-800t^{-1} ?

The answer to derivative of f(x)=800-800t^{-1} is (dt)/(dx)=0

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derivative of f(x)=800-800t^{-1}

derivative of

f (x) = 800 - 800 t^{- 1}

\frac{d t}{d x} = 0

Solution steps

f (x) = 800 - 800 t^{- 1}

Treat

t

t (x)

Differentiate both sides:

0 = \frac{800 \frac{d t}{d x}}{t ^{2}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\int \frac{4}{x ^{6}} d x

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\frac{\partial}{\partial y} (2 x^{3} - 11 x^{2} y + 3 y^{2})

\frac{\partial}{\partial x} (x - y + x y)

\frac{d}{d x} (\frac{6 x - 1}{3 x ^{2} - x})

What is derivative of f(x)=800-800t^{-1} ?
The answer to derivative of f(x)=800-800t^{-1} is (dt)/(dx)=0