derivative P(t)=-5t^2+75t-30

Lösung

ableitung von

P (t) = - 5 t^{2} + 75 t - 30

- 10 t + 75

Schritte zur Lösung

\frac{d}{d t} (- 5 t^{2} + 75 t - 30)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (5 t^{2}) + \frac{d}{d t} (75 t) - \frac{d}{d t} (30)

\frac{d}{d t} (5 t^{2}) = 10 t

\frac{d}{d t} (75 t) = 75

\frac{d}{d t} (30) = 0

= - 10 t + 75 - 0

Vereinfache

= - 10 t + 75

\frac{\partial}{\partial x} (x^{3} - x y + y^{3})

x \to 1 lim (x^{\frac{7}{1 - x}})

\frac{d}{d x} (3 4 x)

\int \frac{4 x}{( x ^{2} + 1 )} d x

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