What is the limit as x approaches infinity of 2^{2x} ?

The limit as x approaches infinity of 2^{2x} is infinity

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limit as x approaches infinity of 2^{2x}

x \to \infty lim (2^{2 x})

\infty

Solution steps

x \to \infty lim (2^{2 x})

Simplify

2^{2 x} : 4^{x}

= x \to \infty lim (4^{x})

Apply the common limit:

x \to \infty lim (a^{x}) = \infty, a > 1

= \infty

d er i v a t i v e y = \frac{3 x - 1}{6 x + 5}

d er i v a t i v e f (x) = (6 x^{2} - x + 7)^{- \frac{5}{3}}

\frac{d y}{d t} = k (y - 60)

\int \frac{x}{( 4 x + 5 ) ^{2}} d x

x \to 1 lim ((x^{3} + 2) (3 - x))

What is the limit as x approaches infinity of 2^{2x} ?
The limit as x approaches infinity of 2^{2x} is infinity