inverselaplace 1/(s-5)

Lösung

inverse laplace transformation

\frac{1}{s - 5}

e^{5 t}

Schritte zur Lösung

L^{- 1} {\frac{1}{s - 5}}

Verwende inverse Laplace-Transformationstabelle:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 5}} = e^{5 t}

= e^{5 t}

y^{^{'}} + 6 y = 60, y (1) = 110

y^{^{'}} = 19 x y

in v erse l a pl a ce \frac{s ^{2}}{s ^{3} + 2 \cdot s ^{2} - 1}

\int_{0}^{7} \frac{6 t}{( t - 8 ) ^{2}} d t

n = 0 \sum \infty n (\frac{3}{4})^{n}