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人気のある微分積分 >

y^{''}+4y=sec^3(2x)

解

y^{^{''}} + 4 y = sec^{3} (2 x)

解

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{tan ( 2 x ) sin ( 2 x )}{8}

解答ステップ

y^{''} (x) + 4 y = sec^{3} (2 x)

線形 ODE を解く:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{tan ( 2 x ) sin ( 2 x )}{8}

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{tan ( 2 x ) sin ( 2 x )}{8}

グラフ

人気の例

tangent y=arctan(-x),\at x=3

t an g e n t y = arctan (- x), at x = 3

integral of sqrt(2-x^2)

\int 2 - x^{2} d x

derivative of 2/(tan(x))

\frac{d}{d x} (\frac{2}{tan ( x )})

derivative x^3+5x^2-63x-140

d er i v a t i v e x^{3} + 5 x^{2} - 63 x - 140

25y^{''}-40y^'+16y=0,y(0)=3,y^'(0)=-2

25 y^{^{''}} - 40 y^{^{'}} + 16 y = 0, y (0) = 3, y^{^{'}} (0) = - 2