derivative of x^3+3x^2-6x-8

Lösung

\frac{d}{d x} (x^{3} + 3 x^{2} - 6 x - 8)

3 x^{2} + 6 x - 6

Schritte zur Lösung

\frac{d}{d x} (x^{3} + 3 x^{2} - 6 x - 8)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (6 x) - \frac{d}{d x} (8)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (8) = 0

= 3 x^{2} + 6 x - 6 - 0

Vereinfache

= 3 x^{2} + 6 x - 6

\int \frac{( arctan ( x ) ) ^{7}}{x ^{2} + 1} d x

d er i v a t i v e f (x) = 3 x^{2} e^{x} + e^{x} (x^{3} + 3)

\int 4 x^{2} x + 9 d x

\int cot (\frac{θ}{7}) d θ

d \to 0 lim (\frac{1}{x + 6} + d)