(\partial)/(\partial t)(t^2+1)

Lösung

\frac{\partial}{\partial t} (t^{2} + 1)

2 t

Schritte zur Lösung

\frac{\partial}{\partial t} (t^{2} + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (t^{2}) + \frac{\partial}{\partial t} (1)

\frac{\partial}{\partial t} (t^{2}) = 2 t

\frac{\partial}{\partial t} (1) = 0

= 2 t + 0

Vereinfache

= 2 t

t an g e n t f (x) = \frac{( x ^{2} )}{x - 5}

x \to 0 lim (\frac{x ( x - 1 )}{x})

d er i v a t i v e \frac{u}{u ^{2} + 4}

l a pl a ce t r an s f or m e^{2 (t - 3)} (3 t^{4} + 2 t^{3} + t)

\frac{\partial}{\partial y} (cos (x - y) - x e^{y})