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Popular Calculus >

integral from-2 to 3 of |x+1|

Solution

\int_{- 2}^{3} ∣ x + 1 ∣ d x

Solution

\frac{17}{2}

+1

Decimal

8.5

Solution steps

\int_{- 2}^{3} ∣ x + 1 ∣ d x

Eliminate Absolutes

= \int_{- 2}^{- 1} - x - 1 d x + \int_{- 1}^{3} x + 1 d x

\int_{- 2}^{- 1} - x - 1 d x = \frac{1}{2}

\int_{- 1}^{3} x + 1 d x = 8

= \frac{1}{2} + 8

Simplify

\frac{1}{2} + 8 : \frac{17}{2}

= \frac{17}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-2 to 3 of |x+1| ?
The integral from-2 to 3 of |x+1| is 17/2