(5y^2-xy)dx+x^2dy=0

Lösung

(5 y^{2} - x y) d x + x^{2} d y = 0

y = \frac{x}{5 ln ( x ) + c _{1}}

Schritte zur Lösung

(5 y^{2} - x y) d x + x^{2} d y = 0

Solve Bernoulli ODE:

y = \frac{x}{5 ln ( x ) + c _{1}}

y = \frac{x}{5 ln ( x ) + c _{1}}

\int - \frac{x}{3} d x

\frac{d}{d x} (- sin (2 x) 2)

(x - 1) y^{^{'}} + (x - 2) y = 0

\frac{d}{d x} (- 2 cos (x))

y ln (x) ln (y) d x + d y = 0