What is the integral of (cos(8x)) ?

The integral of (cos(8x)) is 1/8 sin(8x)+C

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integral of (cos(8x))

\int (cos (8 x)) d x

\frac{1}{8} sin (8 x) + C

Solution steps

\int cos (8 x) d x

Apply u-substitution

= \int cos (u) \frac{1}{8} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{8} sin (u)

Substitute back

u = 8 x

= \frac{1}{8} sin (8 x)

Add a constant to the solution

= \frac{1}{8} sin (8 x) + C

\frac{d}{d x} (\frac{x}{x ^{2} + 8})

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\int \frac{1}{1 + 4 t ^{2}} d t