derivative of 2x^3-4x

解答

\frac{d}{d x} (2 x^{3} - 4 x)

6 x^{2} - 4

求解步骤

\frac{d}{d x} (2 x^{3} - 4 x)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (4 x) = 4

= 6 x^{2} - 4

d er i v a t i v e \frac{2}{3 x ^{4}}

n = 1 \sum \infty \frac{n}{5 + n ^{2}}

a re a 2 x - x^{2}, - 2 x

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x \to 7 lim ((x^{2} - 49) (\frac{( x - 7 )}{∣ x - 7 ∣}))