derivative of 6x^{-2}+9x^{-1}

Lösung

\frac{d}{d x} (6 x^{- 2} + 9 x^{- 1})

- \frac{12}{x ^{3}} - \frac{9}{x ^{2}}

Schritte zur Lösung

\frac{d}{d x} (6 x^{- 2} + 9 x^{- 1})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{- 2}) + \frac{d}{d x} (9 x^{- 1})

\frac{d}{d x} (6 x^{- 2}) = - \frac{12}{x ^{3}}

\frac{d}{d x} (9 x^{- 1}) = - \frac{9}{x ^{2}}

= - \frac{12}{x ^{3}} - \frac{9}{x ^{2}}

\frac{d}{d x} (2 x - x)

n = 1 \sum \infty \frac{n ^{2}}{e ^{n}}

x \to \infty lim (x^{2} - 9, + x)

x \to \infty lim (3 x^{3})

y^{^{''}} - 3 y^{^{'}} + 2 y = 2 e^{t}, y (0) = 0, y^{^{'}} (0) = 0