(\partial)/(\partial y)(x^2+xy-25)

解

\frac{\partial}{\partial y} (x^{2} + x y - 25)

x

解答ステップ

\frac{\partial}{\partial y} (x^{2} + x y - 25)

x

を定数として扱う

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) + \frac{\partial}{\partial y} (x y) - \frac{\partial}{\partial y} (25)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (x y) = x

\frac{\partial}{\partial y} (25) = 0

= 0 + x - 0

簡素化

= x