2ty^'=4y

Lösung

2 t y^{^{'}} = 4 y

y = c_{1} t^{2}

Schritte zur Lösung

2 t y^{'} (t) = 4 y

Solve separable ODE:

y = c_{1} t^{2}

y = c_{1} t^{2}

\frac{d P}{d t} = 0.08 P (1 - \frac{P}{1000})

\int \frac{x ^{2}}{( 21 + 4 x - x ^{2} )} d x

\frac{d}{d x} (\frac{\frac{d}{d x} ( e ^{x} )}{1 + x})

\int 2 x (8 x^{2} - 20)^{2} d x

x \to 1 + lim (1 + \frac{1}{x - 1})