13xy^'-2y=-(x^2)/(y^{12)}

解答

13 x y^{^{'}} - 2 y = - \frac{x ^{2}}{y ^{12}}

y = 13 - ln (x) x^{2} + c_{1} x^{2}

求解步骤

13 x y^{'} (x) - 2 y = - \frac{x ^{2}}{y ^{12}}

求解贝努力方程:

y = 13 - ln (x) x^{2} + c_{1} x^{2}

y = 13 - ln (x) x^{2} + c_{1} x^{2}

\int - \frac{1}{2 x ^{\frac{1}{2}} - x + 1} d x

d er i v a t i v e y = (x^{2} + 1)^{x}

\frac{d}{d x} (\frac{5}{x ^{7}})

l a pl a ce t r an s f or m - 3 e^{4 t}

\int_{1}^{3} \frac{e ^{x}}{e ^{x} - 1} d x