(\partial)/(\partial x)(((3x+5))/(6y+1))

Lösung

\frac{\partial}{\partial x} (\frac{( 3 x + 5 )}{6 y + 1})

\frac{3}{6 y + 1}

Schritte zur Lösung

\frac{\partial}{\partial x} (\frac{( 3 x + 5 )}{6 y + 1})

Behandle

y

als Konstante

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{6 y + 1} \frac{\partial}{\partial x} (3 x + 5)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{6 y + 1} (\frac{\partial}{\partial x} (3 x) + \frac{\partial}{\partial x} (5))

\frac{\partial}{\partial x} (3 x) = 3

\frac{\partial}{\partial x} (5) = 0

= \frac{1}{6 y + 1} (3 + 0)

Vereinfache

\frac{1}{6 y + 1} (3 + 0) : \frac{3}{6 y + 1}

= \frac{3}{6 y + 1}

\int_{0}^{2} π (4 x^{2} - x^{4}) d x

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y^{^{''}} + y^{^{'}} - y = 0

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