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tangent f(x)=2x^2+2x,(-2,-6)

解答

切线

f (x) = 2 x^{2} + 2 x, (- 2, - 6)

解答

y = 2 (25 - 3) x + 85 - 18 or y = - 2 (25 + 3) x - 18 - 85

求解步骤

(- 2, - 6)

处的切线斜率:

m = \frac{2 x ^{2} + 2 x + 6}{x + 2}

计算

f (x) = 2 x^{2} + 2 x

的斜率:

m = 4 x + 2

解

4 x + 2 = \frac{2 x ^{2} + 2 x + 6}{x + 2} : x = - 2 + 5, x = - 2 - 5

求出

x = - 2 + 5

处的切线:

y = 2 (25 - 3) x + 85 - 18

求出

x = - 2 - 5

处的切线:

y = - 2 (25 + 3) x - 18 - 85

y = 2 (25 - 3) x + 85 - 18 or y = - 2 (25 + 3) x - 18 - 85

作图

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