What is the derivative of f(x)= 2/(x^2) ?

The derivative of f(x)= 2/(x^2) is -4/(x^3)

What is the first derivative of f(x)= 2/(x^2) ?

The first derivative of f(x)= 2/(x^2) is -4/(x^3)

derivative of

f (x) = \frac{2}{x ^{2}}

- \frac{4}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{2}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 2 x^{- 2 - 1})

Simplify

2 (- 2 x^{- 2 - 1}) : - \frac{4}{x ^{3}}

= - \frac{4}{x ^{3}}

\frac{d}{d x} (csc^{2} (2 x) - csc (2 x^{2}))

x \to 7 lim (\frac{x ^{2}}{x} - \frac{49}{7})

d er i v a t i v e y = 4 x - 6 x^{3} + \frac{4}{x}

\frac{d y}{d x} + \frac{y}{x} = x

d er i v a t i v e 0.1 (0.7 n^{2} + 9 n + 29)^{(\frac{1}{2})}

What is the derivative of f(x)= 2/(x^2) ?
The derivative of f(x)= 2/(x^2) is -4/(x^3)
What is the first derivative of f(x)= 2/(x^2) ?
The first derivative of f(x)= 2/(x^2) is -4/(x^3)