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Beliebt Rechnen >

(\partial)/(\partial y)(4x^2+y^2-800)

Lösung

\frac{\partial}{\partial y} (4 x^{2} + y^{2} - 800)

Lösung

2 y

Schritte zur Lösung

\frac{\partial}{\partial y} (4 x^{2} + y^{2} - 800)

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x^{2}) + \frac{\partial}{\partial y} (y^{2}) - \frac{\partial}{\partial y} (800)

\frac{\partial}{\partial y} (4 x^{2}) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

\frac{\partial}{\partial y} (800) = 0

= 0 + 2 y - 0

Vereinfache

= 2 y

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