(sin(2θ))^'

Lösung

(sin (2 θ))^{^{'}}

cos (2 θ) \cdot 2

Schritte zur Lösung

(sin (2 θ))^{'}

Wende die Kettenregel an:

cos (2 θ) (2 θ)^{'}

= cos (2 θ) (2 θ)^{'}

(2 θ)^{'} = 2

= cos (2 θ) \cdot 2

h \to 0 lim (\frac{sin ( h )}{7 h})

y \to 0 lim (\frac{5}{y ^{2} + y} - \frac{5}{y})

\int_{3}^{\infty} \frac{1}{x ^{2} - 1} d x

\int 4 \frac{sin ( 2 x )}{sin ( x )} d x

d er i v a t i v e \frac{s - 6}{s + 2}