What is the limit as x approaches 0 of x^2*sin(1/x) ?

The limit as x approaches 0 of x^2*sin(1/x) is 0

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limit as x approaches 0 of x^2*sin(1/x)

x \to 0 lim (x^{2} \cdot sin (\frac{1}{x}))

0

Solution steps

x \to 0 lim (x^{2} sin (\frac{1}{x}))

Apply the Squeeze Theorem:

0

= 0

\int x sin (4 x) cos (4 x) d x

d er i v a t i v e f (x) = \frac{1}{x - 1}

\frac{d}{d x} (x (3 x - 9)^{3})

\int_{0}^{5} \frac{2 x - 1}{x + 1} d x

\int_{0}^{2} x e^{- x^{2}} d x

What is the limit as x approaches 0 of x^2*sin(1/x) ?
The limit as x approaches 0 of x^2*sin(1/x) is 0