What is the sum from n=0 to infinity of 1/(1.5^n) ?

The sum from n=0 to infinity of 1/(1.5^n) is 3

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sum from n=0 to infinity of 1/(1.5^n)

n = 0 \sum \infty \frac{1}{1. 5 ^{n}}

3

Solution steps

n = 0 \sum \infty \frac{1}{1. 5 ^{n}}

Apply Series Geometric Test:

3

= 3

\int - x^{2} - 2 x d x

\int \frac{1}{e ^{6 x}} d x

\frac{d P}{d t} = 50 P - \frac{1}{10} P

\int \frac{cos ( 2 t )}{2} d t

\frac{d}{d x} (\frac{e ^{x}}{e ^{x} - 1})

What is the sum from n=0 to infinity of 1/(1.5^n) ?
The sum from n=0 to infinity of 1/(1.5^n) is 3