What is the integral of (csc^2(x))/4 ?

The integral of (csc^2(x))/4 is -1/4 cot(x)+C

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integral of (csc^2(x))/4

\int \frac{csc ^{2} ( x )}{4} d x

- \frac{1}{4} cot (x) + C

Solution steps

\int \frac{csc ^{2} ( x )}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int csc^{2} (x) d x

Use the common integral:

\int csc^{2} (x) d x = - cot (x)

= \frac{1}{4} (- cot (x))

Simplify

= - \frac{1}{4} cot (x)

Add a constant to the solution

= - \frac{1}{4} cot (x) + C

\int 4 cos (2 x) d x

\int (2 x - 3)^{- 1} (x + 1)^{- 1} d x

im pl i c i t 3 x^{3} + 9 x y^{2} = 5 x^{3}

\frac{d}{d x} (e^{\frac{( x ^{2} )}{2}})

y^{^{''}} - 4 y^{^{'}} + 4 y = t^{3} y^{0}

What is the integral of (csc^2(x))/4 ?
The integral of (csc^2(x))/4 is -1/4 cot(x)+C