What is the tangent of y=7cos(x),\at x= pi/3 ?

The tangent of y=7cos(x),\at x= pi/3 is y=-(7sqrt(3))/2 x+7/2+(7pi)/(2sqrt(3))

tangent of y=7cos(x),\at x= pi/3

tangent of

y = 7 cos (x), at x = \frac{π}{3}

y = - \frac{7 3}{2} x + \frac{7}{2} + \frac{7 π}{2 3}

Solution steps

Find the tangent point:

(\frac{π}{3}, \frac{7}{2})

Find the slope of

y = 7 cos (x) : \frac{d y}{d x} = - 7 sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{7 3}{2}

Find the line with slope m=

- \frac{7 3}{2}

and passing through

(\frac{π}{3}, \frac{7}{2}) : y = - \frac{7 3}{2} x + \frac{7}{2} + \frac{7 π}{2 3}

y = - \frac{7 3}{2} x + \frac{7}{2} + \frac{7 π}{2 3}

y^{^{'}} = 0.4 (10 - x) (5 - x)

\frac{d}{d x} (3 arctan (x + 1 + x^{2}))

\int \frac{x}{x + 1 + 1} d x

\int \frac{4 x ^{2} - x + 1}{x ^{3} - x ^{2} + x - 1} d x

\int ln ∣ x - 1 ∣ d x

What is the tangent of y=7cos(x),\at x= pi/3 ?
The tangent of y=7cos(x),\at x= pi/3 is y=-(7sqrt(3))/2 x+7/2+(7pi)/(2sqrt(3))