What is the tangent of f(x)=2x^2+4x,(-3,6) ?

The tangent of f(x)=2x^2+4x,(-3,6) is y=-8x-18

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tangent of f(x)=2x^2+4x,(-3,6)

tangent of

f (x) = 2 x^{2} + 4 x, (- 3, 6)

y = - 8 x - 18

Solution steps

Find the slope of

f (x) = 2 x^{2} + 4 x : \frac{df ( x )}{d x} = 4 x + 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8

Find the line with slope m=

- 8

and passing through

(- 3, 6) : y = - 8 x - 18

y = - 8 x - 18

x \to 1 lim (ln (x^{5} - 1))

\int_{0}^{1} π (x - x^{12}) d x

\int \frac{3 x ^{2} - x + 2 e}{x ^{2}} d x

\int_{2}^{3} π (x + x^{2})^{2} d x

f (x) = \frac{11}{2} - x^{2}, at x = - 2

What is the tangent of f(x)=2x^2+4x,(-3,6) ?
The tangent of f(x)=2x^2+4x,(-3,6) is y=-8x-18